Finally did some calculation to know which cylinders I have to order:
M= 710kg
Static F/R weight ratio= 63:37 [FONT="]Found here[/FONT]
Dynamic @ 1g approx. 50% rear axle weight transferred to front. Found here
Didn't include the CG Height for simplicity :yum:
Approximate Coefficients of Friction(COF):
Tyres: Concrete (dry) Rubber= 1,0
Brakepads: FERODO Premier = 0,29 (50m @[FONT="]53,4kg/m2,100-to-0 km/h for a focus)[/FONT]
[FONT="]Diameter Brakes (puntoconv.):[/FONT]
[FONT="]Font piston diameter = 54mm[/FONT]
[FONT="]Rear piston diameter = 31mm[/FONT]
Details of the box:
Pedal pivot ratio = 5:1
Pedal travel = 266mm (Calculated with 55deg angle and 275mm height)
->Deceleration= 1 g=> 710kg*9,81m/s2=6.965,1N
Static F/R ratio applied: FF=4.388,013N FR=2.577,087N
Dynamic F/R ratio applied: FF=5.676,56N FR=1.288,54N
Force at pads with coefficient of friction (Fw = µD*FN)
5676.56N = 0.29*Fbrake
FF-Brake=19.574,33N
1288.54N = 0.29*Fbrake
FR-Brake=4.443,25N
Brake cylinder/Piston sizes:
0,625mm Front = 0,625*0,0254=0,015875m
Rear 2 possibilities:
0.700mm Rear = 0,700*0,0254=0,01778m
0,750mm Rear = 0,750*0,0254=0,01905m
Area front cylinder= π*(0,015875m/2)2=0,0001979m2
Area rear cylinder= π*(0,01778m /2)2=0,0002483m2
Area rear cylinder= π*(0,01905m /2)2=0,0002850m2
Area front piston= π*(0.054m/2)2=0,002290m2
Area rear piston= π*(0.031m /2)2=0,0007548m2
Hydraulic Pressure (P=F/A)
F front piston =19.574,33N/2= 9.787,165N per piston
P=9.787,165N/0,002290m2= 4.273.871,179Pa
-> total pressure front = 8.547.742,358Pa
F Rear piston =4443,25N/2= 2221,625N per piston
P=2221,625N /0,0007548m2= 2.943.329,359Pa
-> total pressure rear = 5.886.658,718Pa
Hydraulic Pressure to force at pivot (P=F/A)
F front cylinder at pivot (0.625)= 8.547.742,358Pa*0,0001979m2= 1.691,598N
F rear cylinder at pivot (0.750) = 5.886.658,718Pa*0,0002850m2= 1.677,698N
F rear cylinder at pivot (0.700) = 5.886.658,718Pa*0,0002483m2= 1.461,657N
Force differences f/r have to be as close as possible for the balance bar to be almost straight.
At high braking like this situation rear force can be reduced with the proportion valve, however it doesn’t lower pedal force needed since it’s a reducer….right?
Pedal pivot ratio = 5:1
Actual pedal force req. for 1G deceleration (with 0.625 and 0.750 cylinders), which is the power needed to lock the wheels, if the assumptions of the COF of 1.0 for the tires, the weight and it’s shift of 50% are indeed correct and if the COF of the ferodo test is applicable to the seicento (and of course if I haven’t made a mistake :yum=
(1.691,598N+1.677,698N)/5= 673.86N -> 68.715KG (with 0.750)
(1.691,598N+1.461,657N)/5= 630.65N -> 64.308KG (with 0.700)
Just for reference what 1G of brake power is:
So if all the assumptions and the mathematics are correct it’s a nasty push needed for a full lock…
So I think my math isn’t quite correct somewhere :yum:
But apparently I’m better off with a 0.750 as rear cylinder for a nice straight balance bar as starting position.
Possible Pedal travel length is approx. 26cm, what the actual is going to be is another calculation. But since I can only choose between these 3 types (0.625, 0.700, 0.750), I will see it in real life and not bother calculating that If in fact there will be plenty of stroke left, I can always downsize the cylinders even more to reduce the amount of force needed at the pedals.
M= 710kg
Static F/R weight ratio= 63:37 [FONT="]Found here[/FONT]
Dynamic @ 1g approx. 50% rear axle weight transferred to front. Found here
Didn't include the CG Height for simplicity :yum:
Approximate Coefficients of Friction(COF):
Tyres: Concrete (dry) Rubber= 1,0
Brakepads: FERODO Premier = 0,29 (50m @[FONT="]53,4kg/m2,100-to-0 km/h for a focus)[/FONT]
[FONT="]Diameter Brakes (puntoconv.):[/FONT]
[FONT="]Font piston diameter = 54mm[/FONT]
[FONT="]Rear piston diameter = 31mm[/FONT]
Details of the box:
Pedal pivot ratio = 5:1
Pedal travel = 266mm (Calculated with 55deg angle and 275mm height)
->Deceleration= 1 g=> 710kg*9,81m/s2=6.965,1N
Static F/R ratio applied: FF=4.388,013N FR=2.577,087N
Dynamic F/R ratio applied: FF=5.676,56N FR=1.288,54N
Force at pads with coefficient of friction (Fw = µD*FN)
5676.56N = 0.29*Fbrake
FF-Brake=19.574,33N
1288.54N = 0.29*Fbrake
FR-Brake=4.443,25N
Brake cylinder/Piston sizes:
0,625mm Front = 0,625*0,0254=0,015875m
Rear 2 possibilities:
0.700mm Rear = 0,700*0,0254=0,01778m
0,750mm Rear = 0,750*0,0254=0,01905m
Area front cylinder= π*(0,015875m/2)2=0,0001979m2
Area rear cylinder= π*(0,01778m /2)2=0,0002483m2
Area rear cylinder= π*(0,01905m /2)2=0,0002850m2
Area front piston= π*(0.054m/2)2=0,002290m2
Area rear piston= π*(0.031m /2)2=0,0007548m2
Hydraulic Pressure (P=F/A)
F front piston =19.574,33N/2= 9.787,165N per piston
P=9.787,165N/0,002290m2= 4.273.871,179Pa
-> total pressure front = 8.547.742,358Pa
F Rear piston =4443,25N/2= 2221,625N per piston
P=2221,625N /0,0007548m2= 2.943.329,359Pa
-> total pressure rear = 5.886.658,718Pa
Hydraulic Pressure to force at pivot (P=F/A)
F front cylinder at pivot (0.625)= 8.547.742,358Pa*0,0001979m2= 1.691,598N
F rear cylinder at pivot (0.750) = 5.886.658,718Pa*0,0002850m2= 1.677,698N
F rear cylinder at pivot (0.700) = 5.886.658,718Pa*0,0002483m2= 1.461,657N
Force differences f/r have to be as close as possible for the balance bar to be almost straight.
At high braking like this situation rear force can be reduced with the proportion valve, however it doesn’t lower pedal force needed since it’s a reducer….right?
Pedal pivot ratio = 5:1
Actual pedal force req. for 1G deceleration (with 0.625 and 0.750 cylinders), which is the power needed to lock the wheels, if the assumptions of the COF of 1.0 for the tires, the weight and it’s shift of 50% are indeed correct and if the COF of the ferodo test is applicable to the seicento (and of course if I haven’t made a mistake :yum=
(1.691,598N+1.677,698N)/5= 673.86N -> 68.715KG (with 0.750)
(1.691,598N+1.461,657N)/5= 630.65N -> 64.308KG (with 0.700)
Just for reference what 1G of brake power is:
So if all the assumptions and the mathematics are correct it’s a nasty push needed for a full lock…
So I think my math isn’t quite correct somewhere :yum:
But apparently I’m better off with a 0.750 as rear cylinder for a nice straight balance bar as starting position.
Possible Pedal travel length is approx. 26cm, what the actual is going to be is another calculation. But since I can only choose between these 3 types (0.625, 0.700, 0.750), I will see it in real life and not bother calculating that If in fact there will be plenty of stroke left, I can always downsize the cylinders even more to reduce the amount of force needed at the pedals.
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