ok looking at it quickly; the water absorbs 50% of the output power, the output power was 20kw @ 300l/h, water goes in at 15C, what does it come out at?
this needs the Q = MC (t2-t1) formula (i guess)
we dont know t1 (final temp), but we know
t2 is 15
C is 4.18 (spec heat of water)
Q is 10kw.
M is the mass , so a flow of 300l/h = 300kgs
so; 10 = 300*4.18 (15-t1)
10 = 1254 (15-t1)
10/1254 = 15-t1
10/1254 + t1 = 15
t1 = 15 -10/1254
t1 = 15 - 0.008 = 14.992
hang on that cant be right, i made a mistake when calculating M, maybe it should be kg/s per second not hour, i cant remember.
i'm going toilet, give me 2 mins.