Technical 215/40/18 on a standard GP??

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Technical 215/40/18 on a standard GP??

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Nov 26, 2010
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Hi all,

I was just wondering, as the title says, if 215/40/18 alloys/tyres will go on a standard GP (1.2 Stripe), without rubbing, etc. (As far as I'm aware, the abarth esseesse uses these?) And would I need any spacers or anything?

Also, I am looking to get the car lowered (Eibach Sportlines appear to be the best option), so would they still fit if I did that?

Any help is much appreciated. Thanks!
 
Agreed! 18" on your car is not a good idea buddy, it may look good but not worth the potential damage.:(
Id see if i could find some 16's and then lower, even 17's could cause damage and besides which will make your car slower.
 
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Just out of pure curiosity. How does the bigger the wheel the more strain on the gearbox come about? Probably a very silly question! Haha. I'm kinda seeing it now as I'm thinking about it I think actually!
 
Just out of pure curiosity. How does the bigger the wheel the more strain on the gearbox come about? Probably a very silly question! Haha. I'm kinda seeing it now as I'm thinking about it I think actually!

the extra weight mainly, and the distance of the weight in relation to the centre of the wheel, 'more centrifugal' force basically makes it harder to remolve the wheel - this also has a negative effect on braking forces. If you found some super lightweight alloys i dont see it as much of an issue if you drove around 'normally'
 
Thanks for the all the answers. I am aware of these gearbox problems, but these are super lightweight OZ alloys and I will make 100% sure on the gearbox before buying. I was just focusing on the size at the moment, so if anyone could help me on that it would be good. Again, thanks for the warnings though :)
 
the extra weight mainly, and the distance of the weight in relation to the centre of the wheel, 'more centrifugal' force basically makes it harder to remolve the wheel - this also has a negative effect on braking forces. If you found some super lightweight alloys i dont see it as much of an issue if you drove around 'normally'

Your talking B******s!.. Regardless of extra strain, if its the same rolling radius as original wheels, it won't be any harm.
 
Your talking B******s!.. Regardless of extra strain, if its the same rolling radius as original wheels, it won't be any harm.

Yeah all my engineering design qualifications must be a load of ******** then (y) rolling radius will be the same on all the grande punto wheels, weather its a 15 inch or 17. Go and read up on centrifugal forces and (force x distance) equations and then comment something helpfull
 
Forgive me if I'm wrong here but surely a 18inch wheel has a larger rolling radius than a 16 inch wheel?

And if not.... Why not?

(Pure curiosity!)
 
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P.S. Centrifugal forces don't exist, it's centripetal force... unless my physics qualificiations are ********?! :)
 
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Forgive me if I'm wrong here but surely a 18inch wheel has a larger rolling radius than a 16 inch wheel?

And if not.... Why not?

(Pure curiosity!)

because (generally) smaller wheels have a tyre size that makes up for the difference ie: super low profile tyres on 18's
 
P.S. Centrifugal forces don't exist, it's centripetal force... unless my physics qualificiations are ********?! :)

Centrifugal force (from [ame="http://en.wikipedia.org/wiki/Latin_language"]Latin - Wikipedia, the free encyclopedia@@AMEPARAM@@/wiki/File:Rome_Colosseum_inscription_2.jpg" class="image"><img alt="Alt text" src="http://upload.wikimedia.org/wikipedia/commons/thumb/b/b7/Rome_Colosseum_inscription_2.jpg/200px-Rome_Colosseum_inscription_2.jpg"@@AMEPARAM@@commons/thumb/b/b7/Rome_Colosseum_inscription_2.jpg/200px-Rome_Colosseum_inscription_2.jpg[/ame] centrum, meaning "center", and fugere, meaning "to flee") represents the effects of [ame="http://en.wikipedia.org/wiki/Inertia"]Inertia - Wikipedia, the free encyclopedia[/ame] that arise in connection with rotation and which are experienced as an outward force away from the center of rotation. In [ame="http://en.wikipedia.org/wiki/Newtonian_mechanics"]Classical mechanics - Wikipedia, the free encyclopedia@@AMEPARAM@@/wiki/File:Tir_parab%C3%B2lic.png" class="image"><img alt="" src="http://upload.wikimedia.org/wikipedia/commons/thumb/7/72/Tir_parab%C3%B2lic.png/220px-Tir_parab%C3%B2lic.png"@@AMEPARAM@@commons/thumb/7/72/Tir_parab%C3%B2lic.png/220px-Tir_parab%C3%B2lic.png[/ame], the term centrifugal force is used to refer to one of two distinct concepts: an [ame="http://en.wikipedia.org/wiki/Inertial_force"]Fictitious force - Wikipedia, the free encyclopedia@@AMEPARAM@@/wiki/File:Accelerating_car.PNG" class="image"><img alt="" src="http://upload.wikimedia.org/wikipedia/commons/thumb/1/17/Accelerating_car.PNG/350px-Accelerating_car.PNG"@@AMEPARAM@@commons/thumb/1/17/Accelerating_car.PNG/350px-Accelerating_car.PNG[/ame] (also called a [ame="http://en.wikipedia.org/wiki/Fictitious_force"]Fictitious force - Wikipedia, the free encyclopedia@@AMEPARAM@@/wiki/File:Accelerating_car.PNG" class="image"><img alt="" src="http://upload.wikimedia.org/wikipedia/commons/thumb/1/17/Accelerating_car.PNG/350px-Accelerating_car.PNG"@@AMEPARAM@@commons/thumb/1/17/Accelerating_car.PNG/350px-Accelerating_car.PNG[/ame]) observed in a non-inertial [ame="http://en.wikipedia.org/wiki/Frame_of_reference"]Frame of reference - Wikipedia, the free encyclopedia@@AMEPARAM@@/wiki/File:Two_reference_frames.PNG" class="image"><img alt="" src="http://upload.wikimedia.org/wikipedia/commons/thumb/3/3f/Two_reference_frames.PNG/320px-Two_reference_frames.PNG"@@AMEPARAM@@commons/thumb/3/3f/Two_reference_frames.PNG/320px-Two_reference_frames.PNG[/ame], and a reaction force corresponding to a [ame="http://en.wikipedia.org/wiki/Centripetal_force"]Centripetal force - Wikipedia, the free encyclopedia@@AMEPARAM@@/wiki/File:Centripetal_force_diagram.svg" class="image"><img alt="" src="http://upload.wikimedia.org/wikipedia/commons/thumb/c/c9/Centripetal_force_diagram.svg/220px-Centripetal_force_diagram.svg.png"@@AMEPARAM@@commons/thumb/c/c9/Centripetal_force_diagram.svg/220px-Centripetal_force_diagram.svg.png[/ame].
 
Ah yes, I forgot about the low profile tyres. Still though at the end of the day, if the wheels are heavier (like you say), more mass means more work needs to be done to get them going! Nobody can argue with that. And also objects in motion like to stay in motion so braking force will also be affected with heavier wheels. I agree with you.

Apart from the bit about centrifugal forces. It's a 'fake' force. It's the centripetal force that's acting towards the centre of the wheel. Centrifugal force is the outward force which isn't really there. It's only there if you imagine a hammer thrower releasing his hammer, then it moves outwards. But it only moves outwards due to there being no centripetal force anymore. And one other thing, never take Wikipedia's word for anything! Even though even wikipedia in this instance has called it a 'fictitious force' ;);)
 
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Ah yes, I forgot about the low profile tyres. Still though at the end of the day, if the wheels are heavier (like you say), more mass means more work needs to be done to get them going! Nobody can argue with that. And also objects in motion like to stay in motion so braking force will also be affected with heavier wheels. I agree with you.

Apart from the bit about centrifugal forces. It's a 'fake' force. It's the centripetal force that's acting towards the centre of the wheel. Centrifugal force is the outward force which isn't really there. It's only there if you imagine a hammer thrower releasing his hammer, then it moves outwards. But it only moves outwards due to there being no centripetal force anymore. And one other thing, never take Wikipedia's word for anything! Even though even wikipedia in this instance has called it a 'fictitious force' ;);)

Im at work and wikipedia was the quickest to get to :rolleyes: even though it is a 'fake' force it is still a valid way of measuring the forces acting on an object. Thats also pretty much what i was saying earlier that a larger wheel will weigh more (unless its a really lightweight one which could make a difference)
 
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